Chuyển đổi hệ cơ số trong C

/**
 * Chuong trinh chuyen doi he co so trong C
 * Bai tap nay su dung bang ASCII de chuyen doi so nguyen thanh kieu ky tu
 * Link tham khao: https://vi.wikipedia.org/wiki/ASCII
 *  
 * @author viettuts.vn
 */

#include<stdio.h>

const char CHAR_55 = 55;
const char CHAR_48 = 48;

/**
 * chuyen doi so nguyen n sang he co so b
 * 
 * @author viettuts.vn
 * @param n: so nguyen
 * @param b: he co so
 */
int convertNumber(int n, int b) {
    if (n < 0 || b < 2 || b > 16 ) {
        printf("He co so hoac gia tri chuyen doi khong hop le!");
        return 0;
    }
    int i;
    char arr[20];
    int count = 0;
    int m;
    int remainder = n;
    while (remainder > 0) {
        if (b > 10) {
            m = remainder % b;
            if (m >= 10) {
                arr[count] = (char) (m + CHAR_55);
                count++;
            } else {
                arr[count] = (char) (m + CHAR_48);
                count++;
            }
        } else {
            arr[count] = (char) ((remainder % b) + CHAR_48);
            count++;
        }
        remainder = remainder / b;
    }
    // hien thi he co so
    for (i = count - 1; i >= 0; i--) {
        printf("%c", arr[i]);
    }
    return 1;
}

/**
 * Ham main
 */
int main() {
    int n = 12;
    printf("So %d trong he co so 2 = ", n);
    convertNumber(n, 2);
    printf("\nSo %d trong he co so 16 = ", n);
 convertNumber(n, 16);
    return 1;
}